화학반응Engineering 2판 解法(해법)
페이지 정보
작성일 20-07-02 14:35본문
Download : 솔루션 기타 반응공학 solution.pdf
the engineering of chemical reactions , schmidt , 2nd edition
Download : 솔루션 기타 반응공학 solution.pdf( 22 )
화학반응Engineering 2판 解法(해법)
순서
솔루션,기타,솔루션
the engineering of chemical reactions , schmidt , 2nd edition1장~12장 / 화학반응공학 2판 솔루션 , 화학반응공학 2판 솔루션기타솔루션 , 솔루션
설명
솔루션/기타
the engineering of chemical reactions , schmidt , 2nd edition
1장~12장 / 화학reaction response공학 2판 해결책
Semiconductor Physics and Devices: Basic Principles, 3rd edition Solutions Manual
Chapter 1 Problem Solutions
Chapter 1
Problem Solutions
1.1 (a) fcc: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms Total of 4 atoms per unit cell (b) bcc: 8 corner atoms × 1/8 = 1 atom 1 enclosed atom = 1 atom Total of 2 atoms per unit cell (c) Diamond: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms 4 enclosed atoms = 4 atoms Total of 8 atoms per unit cell 1.2 (a) 4 Ga atoms per unit cell Density = 4 atoms per cell, so atom vol. = 4 Then 4 Ratio =
FG 4πr IJ H3K
3
16 2 r (c) Body-centered cubic lattice 4 d = 4r = a 3 ⇒ a = r 3 Unit cell vol. = a =
3
FG 4πr IJ H 3…(생략(省略))
1장~12장 / 화학반응Engineering 2판 解法(해법)
다.