[전기] Fundamental of Electric Circuits 3e Alexander Sadiku
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작성일 20-04-14 18:55
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Fundamental of Electric Circuits 3e - Alexander Sadiku -
How many coulombs are represented by these amounts of electrons:
설명
(c) ()()nC e5e3tqt2-t−−=
솔루션,Fundamental,Electric,Circuits,3판,Alexander,Sadiku
Chapter 1, Problem 1
(d) i=dq/dt = 1200120ππcost pA
[이용대상] Fundamental of Electric Circuits 3e - Alexander Sadiku -
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(b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C
Chapter 1, Problem 2.
PROPRIETARY
(e) ()Ct 50cos204μtetq−=
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(a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C
(b) i = dq/dt = (16t + 4) A
(a) (b) 1710482.6×181024.1×
Determine the current flowing through an element if the charge flow is given by
Fundamental of Electric Circuits 3e - Alexander Sadiku - [참고자료] Fundamental of Electric Circuits 3e - Alexander Sadiku - [자료범위] Fundamental of Electric Circuits 3e - Alexander Sadiku - [이용대상] Fundamental of Electric Circuits 3e - Alexander Sadiku -
(d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C
Chapter 1, Solution 1
(d) ()pCt sin10 120tqπ=
(a) ()()mC 83+=ttq
(c) i = dq/dt = (-3e-t + 10e-2t) nA
(b) ()C 2)482t-t(tq+=
(e) i =dq/dt = −+−ettt48050100050(cossin) Aμ
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[전기] Fundamental of Electric Circuits 3e Alexander Sadiku
(c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C
(a) i = dq/dt = 3 mA
Chapter 1, Solution 2
순서
[data(資料)범위] Fundamental of Electric Circuits 3e - Alexander Sadiku -
[참고data(資料)] Fundamental of Electric Circuits 3e - Alexander Sadiku -
(c) (d) 191046.2×2010628.1×
다.
